Find the (n-1) * term of the A.P. 1/n,2/n,3/n....
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(n-1)th term of this ap is
a + (n-1)d {a = 1/n , n = n-1 , d = 1/n)
putting this value , we will get
1/n + {(n-1)-1)}1/n
1/n + (n-2) * 1/n
1/n + (n-2)/n
(n-1)/n
Therefore the (n-1)th term of this A.P is (n-1)/n
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