Question

find the n when 6^2n+1/36=6^3​

Answer 1

SoluTion :-

$\sf {\rightarrowtail \ \frac{6^{2n+1}}{36}=6^{3} }\\\\\\\\\sf {\rightarrowtail \ \frac{6^{2n+1}}{6^{6}}=6^{3} }\\\\\\\\\sf {\rightarrowtail \ 6^{2n+1-2} =6^{3} }\\\\\\\\\sf {\rightarrowtail \ 6^{2n-1}=6^{3}}$

Since base is same,

$\sf {\rightarrowtail \ 2n-1=3}\\\\\\\sf {\rightarrowtail \ 2n=4 }\\\\\\\sf {\rightarrowtail \ n=\frac{4}{2} }\\\\\\\sf {\rightarrowtail \ n=2}$

Answer 2

Answer:

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