find the name of a, if 2x-3 is a factor of 2x^4-x^3-3x^2-2x+9.
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Answer:
Step-by-step explanation:
let p(x)= 2x^4-x^3-3x^2-2x+9
then, g(x)= 2x-3
if g(x)= 0
2x-3=0
2x=3
x=3/2
p(3/2)= 2×(3/2)^4-(3/2)³-2×3/2+9
0= 2×729/16-81/8-3+9
0= 729/8-81/8-3+9
0= (729-81-24+72)/8
0= 694
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