Question

find the natural and real roots of the quadratic equation (x-root2)^2-2(x+1)=0

Answer 1

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Answer 2

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${(x - \sqrt{2} }^{2} ) - 2(x + 1) = 0$

${x}^{2} - 2 \sqrt{2} x + 2 - 2x - 2 = 0$

${x}^{2} - 2 \sqrt{2} + 2x = 0$


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