Question

Find the natural frequency of a body whose acceleration due to gravity g is 9.8m/s^2 and length of the pendulum is 1m.
Use f= 1/2pi root (g/l)​

Answer 1

Answer:

Frequency of simple pendulum ( F ) =1/2π × √g/l

F = 1/2π ×√ 9.8/1

F = 1/2π ×3.13

F= 0.49 hertz

Explanation:

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