Question

find the natural number between 100 and 999 which are divided by 6 also find sum of the number divisible by 6​

Answer 1

89 natural number

explanation:-

no. divisible by 2&5 must be divisible by 10

Form an AP of natural number present between 101 & 999

AP = 110, 120, 130,............, 990

from the AP we concluded

a = 110

d = 10

nth term of the AP = 990

a+(n-1)d=990

110+(n-1)10=990

(n-1)10=990-110

(n-1)= 880/10

n-1=88

n=88+1

n=89

natural number present between 101 & 109 = 89 is the answer

Answer 2

natural number between 100 and 199 is 100