Question

Find the natural number whose square diminished by 4 , is equal to thrice of 8 more than the given number ?​

Answer 1

Answer:

Step-by-step explanation

(x^2)-4=3*(8+X)

X^2 -4=24+3x

X^2=28+3x

X^2-3x-28=0

Sum=-3

PDT=-28

(-7,4)

=X^2-7x+4x-28

X(x-7)+4(x-7)

(X+4)(x-7)=0

X=-4 or 7

X = 7.....(X is natural no.)