Question

Find the natural root of 3x^2+7x+2

Answer 1

Answer:

A. 3x

2

+7x+2=0

△=b

2

−4ac=7

2

−4(2)(3)=49−24=25>0

∴Roots are real and positive

B. (x+3)

2

+4x+7=0

x

2

+9+6x+4x+7=0

x

2

+10x+16=0

△=b

2

−4ac=100−4(16)=36=6

2

>0

∴Roots are real and positive

C. 2x

2

−8x+34=0

△=8

2

−4(2)(34)<0

∴ Roots are imaginary

D. x

2

+2

3

x−1=0

△=(2

3

)

2

+4(1)=12+4=16>0

Answer 2

x = b^2-4ac

x=7^2-4×3×2

x=49- 24

x=25

nature of roots are real and distinct

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