Find the natural root of 3x^2+7x+2
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Answered by
0
Answer:
A. 3x
2
+7x+2=0
△=b
2
−4ac=7
2
−4(2)(3)=49−24=25>0
∴Roots are real and positive
B. (x+3)
2
+4x+7=0
x
2
+9+6x+4x+7=0
x
2
+10x+16=0
△=b
2
−4ac=100−4(16)=36=6
2
>0
∴Roots are real and positive
C. 2x
2
−8x+34=0
△=8
2
−4(2)(34)<0
∴ Roots are imaginary
D. x
2
+2
3
x−1=0
△=(2
3
)
2
+4(1)=12+4=16>0
Answered by
2
x = b^2-4ac
x=7^2-4×3×2
x=49- 24
x=25
nature of roots are real and distinct
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