Find the nature and power of a lens which forms a real and inverted image
of magnification -1 at a distance of 40 cm from its optical centre.
Answers
Answered by
1
Answer:
#love.....
Explanation:
Given magnification m=−1 and object distance u=−20cm
We know magnification m=
u
−v
v=−mu=(−1)(−20)=20cm
Now from lens formula we have,
v
1
−
u
1
=
f
1
20
1
−
20
−1
=
f
1
f=10cm
Now powerp=
f
1
=
100
10
1
=10 D
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