Question

FInd the nature of root by calculating the value of discriminate help!!!!​

Answer 1

Answer:

discriminant = 0

1 real and repeated solution

Step-by-step explanation:

$\sqrt{3}x^{2} +2\sqrt{3} x+\sqrt{3} = 0\\ a = \sqrt{3} ; b = 2\sqrt{3} ; c = \sqrt{3} \\\\ b^{2} -4ac = (2\sqrt{3} )^{2} -4(\sqrt{3})(\sqrt{3})\\\\\\= (4 * 3) - (4 * 3)\\=12 - 12 = 0$

here, the discriminant is 0  

so, the quadratic equation will have 1 real and repeated solution

hope it helps

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