Question

find the nature of root of the equation 5x-3√5x+1=0​

Answer 1

Answer:

Step-by-step explanation:

See the screenshot

Answer 2

Question:

(with correction)

Find the nature of root of the equation 5x²-3√5x+1=0

Solution:

Comparing 5x²-3√5x+1=0 with

ax² + bx + c =0

we get,

a = 5

b = -3√5

c = 1

Discriminant (D) = b² - 4ac

D = (-3√5)² - 4 × 5 × 1

= 45 - 20

= 25

Since,

D > 0

The quadratic equation has Real and Distinct roots.

_________________________

Other cases:

• D < 0

If the discriminant is greater than zero, this means that the quadratic equation has no real roots.

• D = 0

If the discriminant is equal to zero, this means that the quadratic equation has real and identical roots.