Question

find the nature of root of the quadratic equation 5x2-3x+1​

Answer 1

Answer:

As, D = b² - 4ac = (-3)² - 4*5*1 = 9 - 20 = -11

Since D < 0.Hence, roots are imaginary and distinct.

Step-by-step explanation:

Answer 2

The root of the given equation is imaginary, i.e. two nonreal roots.

Given:

The quadratic equation 5x²-3x+1​  

To find:

Find the nature of the root of the quadratic equation

Solution:

Formula used:

The discriminant of the quadratic equation ax²+bx+c is given by  

               Discriminant, Δ = b² - 4ac  

Given the quadratic equation 5x²-3x+1​    

Compare the given equation with ax²+bx+c  

=> a = 5, b = -3 and c = 1

By the given formula,

Discriminant, Δ = (-3)² - 4(5)(1)

 

= 9 - 20 = - 11

Here Discriminant < 0  

Therefore,

The root of the given equation is imaginary, i.e. two nonreal roots.

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https://brainly.in/question/12307233  

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