Math, asked by arvindlogesh66, 3 months ago

Find the nature of
roots 6x3-3-2=0​

Answers

Answered by amangarnayak04
0

Answer:2x2 - 6x + 3 = 0. Comparing this equation with ax2 + bx + c = 0, we get. a = 2, b = -6, c = 3. Discriminant = b2 - 4ac. = (-6)2 - 4 (2) (3). = 36 - 24 = 12. As b2 - 4ac ...

Step-by-step explanation:

Answered by rekhabansal8012
1

Answer:

6*3-3-2

18-5

13

roots are real and distinct.

Step-by-step explanation:

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