Math, asked by ypreddy463, 11 months ago

find the nature of roots for 4x^2 - √3x-9 = zero

Answers

Answered by gnagamokshi

1

Answer:

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Step-by-step explanation:

4x^2-√3x-9=0

b^2-4ac=0

(√3)^2-4*4*(-9)

3-16*(-9)

3+144

147>0

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