Math, asked by prince3181, 1 year ago

find the nature of roots for the quadratic equation 2x^2-√5x+1=0​

Answers

Answered by krimusa7524
7

Discriminant = b^2 -4ac

Equation : 2x^2 - root 5x + 1

a = 2

b = - root 5

c = 1

So,

(-root 5)^2 - 4× 2 ×1

= 5 - 8

= -3 < 0

So , the root will not be real .

Answered by ChitranjanMahajan
4

Given:

2x² - √5x + 1 = 0

To Find:

Find the nature of roots.

Solution:

We know that,

Discriminant = b² -4ac

Equation: 2x²- √5x + 1

Here, we have

a = 2

b = -√5

c = 1

So,

Discriminant = (-√5)² - 4×2×1

                     = 5 - 8

                     = -3

This implies that the since D < 0, the quadratic equation will not have any real roots.

Hence, the root will not be real.

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