Question

Find the nature of roots, if real roots exit find them. 2x square -6x+3=0

Answer 1

Answer:

real and distinct

because D>0

Explanation:

Answer 2

Answer:

D = √b²-4ac

D = √6²-4*2*3

D = √36-24

D = √12 = 2√3

since D>0

roots are real and unequal ..

now roots = 6±2√3/4

= (3+√3/2) & (3-√3/2) (Ans)

(Mark as brainlist)