find the nature of roots of equation 2x^2+8x-4=0
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On compairing with ax²+bx+c=0
a=2 ,b=8,c=-4
∆=b²-4ac =(8²-4*2*(-4)
=64+32
=96
x=(-b+-√(b²-4ac))/2a
x=(-8+-√96)/4
x=-8/4 +-√96/4
x=-2+4√6/4. x=-2–4√6/4
x=-2+√6. x=-2-√6
Clearly, the discriminant of the given quadratic equation is positive but not a perfect square.
Therefore, the roots of the given quadratic equation are real, irrational and unequal.
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