Question

find the nature of roots of equation 3x^2-4√3x+4=0​

Answer 1

Answer:

find discriminate then you will get the answer

Answer 2

Step-by-step explanation:

$3 {x}^{2} - 4 \sqrt{3} x + 4 = 0 \\ 3 {x}^{2} - 2 \sqrt{3} x - 2 \sqrt{3} x + 4 = 0 \\ \sqrt{3} x( \sqrt{3} x - 2) - 2( \sqrt{3} x - 2) = 0 \\ ( \sqrt{3} x - 2)( \sqrt{3} x - 2) = 0 \\ x = \frac{2}{ \sqrt{3} } \\ \\ hope \: it \: will \: help \: you$