Question

Find the nature of roots of given quadratic equation
J2 2 + 7 xt 5 V2=0o ub the real roots exist Find them.​

Answer 1

Answer:

Given,

2x2+7x+52=0

or, 2x2+2x+5x+52=0

or, x2(x+2)+5(x+2)=0

or, (x2+5)(x+2)=0

⇒x=−25,−2.

These are the required roots

Answer 2

Answer:

i wonder why my rank isn't increasing

Step-by-step explanation:

Given, 2x

2

−3x+5=0

Comparing with the standard quadratic equation is ax

2

+bx+c=0

Here, a=2, b=−3, c=5

Now, D=b

2

−4ac

=9−4×2×5

=−31

Here, the discriminant is negative.

Thus the quadratic question does not have any real roots.