Find the nature of roots of quadratic equation 2x sq. + 3x - 7=0
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Answered by
6
To find the nature of roots,find Discriminate

a =2
b=3
c= -7

D >0, So, roots are real and distinct.
a =2
b=3
c= -7
D >0, So, roots are real and distinct.
priya686610:
Thanku so much
Answered by
6
Hey Mate !
Good morning
Here's your answer
a = 2
b = 3
c = - 7
As we know that ,
Discriminate = b² - 4 ac
Discriminate = 3² - 4 × 2 × ( - 7 )
=> 9 - 8 × ( -7 )
=> 9 + 56
=> 65
Here ,
D is greater than 0
Therefore , Roots are distinct .
Good morning
Here's your answer
a = 2
b = 3
c = - 7
As we know that ,
Discriminate = b² - 4 ac
Discriminate = 3² - 4 × 2 × ( - 7 )
=> 9 - 8 × ( -7 )
=> 9 + 56
=> 65
Here ,
D is greater than 0
Therefore , Roots are distinct .
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