Question

find the nature of roots of quadratic equation from 4 x square + 4 root 3 X + 3 equal to zero ​

Answer 1

Answer :-

Given Quadratic equation has two equal roots. The graph of the quadratic equation cuts X - axis only at on point.

Solution :-

4x² + 4√3 x + 3 = 0

Comparing with ax² + bx + c = 0 we get,

• a = 4
• b = 4√3
• c = 3

Discriminant = b² - 4ac

= ( 4√3 )² - 4( 4 )( 3 )

= 4² * ( √3 )² - 48

= 16 * 3 - 48

= 48 - 48

= 0

Since, the discriminant is equal to 0, the given quadratic equation has two equal roots. The graph of the quadratic equation cuts X - axis only at on point.

Answer 2

Step-by-step explanation:

to find the root we use:

bsquare-4ac

Equation:4x^2-4√3x+3

so we get (-4√3)^2-(4×4×3)

16(3)-16(3)

48-48

=0