Question

find the nature of roots of quadratic equation x^2+x-5=0 ​

Answer 1

Answer:

Real, Distinct and Irrational

Step-by-step explanation:

x² + x - 5 = 0

Discriminant Δ = b² - 4ac

⇒ Δ = 1 - 4(1)(-5) = 1 + 20 = 21

As Δ > 0, The roots of the given equation are Real and Distinct (unequal).

As Δ is not a perfect square (As 21 is not a perfect square), The roots are irrational.

Hence, in conclusion, The roots of x² + x - 5 = 0 are Real, Distinct and Irrational.

Hoping that I have not made any mistakes, You're welcome.

Hope you have found my answer useful. If my answer deserves a brainliest, do mark it, Thanks !

GeniusH

Answer 2

Answer:

x^2 + x - 5

(b^2 - 4ac)

1 - 4 * 1 * -5

1 + 20

21

real and unequal