Question

find the nature of roots of quadratic equation x^2+x-5=0


Pls help.. ​

Answer 1

Answer:

Answer

Answer2x

Answer2x 2

Answer2x 2 +5x+5=0

Answer2x 2 +5x+5=0This is of the form ax

Answer2x 2 +5x+5=0This is of the form ax 2

Answer2x 2 +5x+5=0This is of the form ax 2 +bx+c=0, where a=2,b=5,c=5

Answer2x 2 +5x+5=0This is of the form ax 2 +bx+c=0, where a=2,b=5,c=5Therefore,

Answer2x 2 +5x+5=0This is of the form ax 2 +bx+c=0, where a=2,b=5,c=5Therefore,D=b

Answer2x 2 +5x+5=0This is of the form ax 2 +bx+c=0, where a=2,b=5,c=5Therefore,D=b 2

Answer2x 2 +5x+5=0This is of the form ax 2 +bx+c=0, where a=2,b=5,c=5Therefore,D=b 2 −4ac=25−40=−15<0

Answer2x 2 +5x+5=0This is of the form ax 2 +bx+c=0, where a=2,b=5,c=5Therefore,D=b 2 −4ac=25−40=−15<0Therefore, the equation has no real roots.