find the nature of roots of quadratic equations 2x^2-2√6x+3=0
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EXPLANATION.
Nature of roots of quadratic equation.
2x² - 2√6x + 3 = 0.
As we know that,
D = discriminant Or b² - 4ac.
Put the value in the equation, we get.
⇒ D = (-2√6)² - 4(2)(3).
⇒ D = 24 - 24.
⇒ D = 0.
Nature of Roots are real and equal.
MORE INFORMATION.
D = discriminant Or b² - 4ac.
(1) If D < 0.
One roots : α + iβ.
Other roots : α - iβ.
(2) If D > 0.
One roots : α + √β.
Other roots : α - √β.
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