find the nature of roots of quadratic equations x^2-6x+9=0
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Answered by
5
Answer:
= x² − 3x − 3x + 9 = 0
= x (x−3) − 3 (x−3) = 0
= (x−3) (x−3) = 0
= (x−3)² = 0
= x − 3 = 0
or x = 3
Answered by
0
Answer:
roots = 3
Step-by-step explanation:
hope you understand solution
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