Find the nature of roots of the following equation. If they are real, find them.
(b) 3x2 - 6x + 2 = 0
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Answer:
x = 1.577 or 0.423
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Step-by-step explanation:
a = 3
b = - 6
c = 2
b² -4ac = (-6)² - 4×3×24 = 36 - 24 = 12
The roots are real and distinct.
x = - b ± √b² - 4ac / 2a
= -(-6) ± √12/2×3
= 6 ± 3.464 / 6
= 6 + 3.464 / 6 or = 6- 3.464 / 6
= 9.464/6 = 2.536 / 6
= 1.577 = 0.423
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