Question

Find the
nature of roots of the
following quadratic equations If the real
Roots exist, find them

3y²-12y-9=0​

Answer 1

Step-by-step explanation:

9y-12y=+9

-3y=9

y=9/-3

y=-3

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Answer 2

Answer: 2±$\sqrt{7}$; Irrational

Step-by-step explanation:

3y^2 - 12y - 9 =0

3(y^2 - 4y -3) = 0

y^2 - 4y -3 = 0

D= b^2-4ac

D = 16 - 4.1.(-3)

D = 16 + 12 = 28

Roots = (4± $\sqrt{28}$)/2 = (4±2$\sqrt{7}$)/2 = 2±$\sqrt{7}$

Nature of Roots: Irrational

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