Question

Find the nature of roots of the following quadratic equation.

x^3 - 4x^2 - x + 1= (x-2)^3

Real and equal

Real and different

Roots do not exist

None of the above

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Answer 1

Answer:

Answer=Real and different

Step-by-step explanation:

x^3 - 4x^2 - x + 1= (x-2)^3

x^3-4x^2-x+1=x^3-8-6x(x-2)

x^3-4x^2-x+1=x^3-8-6x^2+12x

-4x^2-x+1=-8-6x^2+12x

2x^2-13x+9

a=2

b=-13

c=9

Discriminant, D=b^2−4ac=169−72=97

Since D>0, the roots are real but not equal.