Question

find the nature of roots of the following x²-3x+3=0​

Answer 1

Answer:

D=b^2-4ac

D=(-3)^2-4.1.3

D=-3<0

So root is imaginary

Step-by-step explanation:

Answer 2

Answer:

I hope it will help you

Step-by-step explanation:

Let x2 - 3x +3 = 0 Comparing with, ax2 + bx + c =0

therefore,

a = 1 ,b = ( -3) ,c = 3 ......... (1)

∆=b2 - 4 a c

from (1),

∆ = (-3) square - 4 x 1 x 3

∆= 9 - 12

∆ = (-3)

∆ > ( - 3 )

therefore,

the root of the given Quadratic equation are Real and Not-equal.

Correct✔ answer