Find the nature of roots of the given quadratic equation 2x²-6x+3=0
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9
Answer:
THE QUADRATIC EQUATION HAVE TWO DISTINCT REAL ROOTS
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Answered by
8
Step-by-step explanation:
comparing equation with ax²+bx+c=0
a=2 b= -6 c= 3
delta=b²-4ac -6²-4×2×3=0
= 36-8×3=0
36-24=0
12=0
12>0
therefore, the nature of the root is real and unequal
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