find the nature of roots of the quadractic equation 3x2-6√5x+8=0
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Answered by
1
Answer:
Nature of roots of the equation is Real and Distinct roots
Answered by
0
Answer:
Comparing 3x2-6√5x+8=0 with
ax² + bx + c = 0
a = 3×2 b = 6√5 c = 8
b² - 4ac = ( 6√5) ² - 4 (3)2(8)
= 180 - 4(6)8
=180 - 192
= (-12)
Thus, b² - 4ac < 0
THE ROOT ARE NOT REAL
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