Find the nature of roots of the quadratic equation 2x square -rootx +1=0
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No real roots because discriminant is less than 0
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Answer:
Step-by-step explanation:
Given equation: 2x²-√5x+1
Discriminant: b²-4ac
Here,a=2
b=√5
c=1
(√5)²-4(2)(1)=D
5-8=D
-3<0
Here,discriminant is lesser than zero so the equation have no real roots:))
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