Question

Find the nature of roots of the quadratic equation
√2X²-3/√2X+1/√2=0​

Answer 1

Answer:

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Answer 2

HELLO !

Answer:

D > 0, Roots are real & distinct

Step-by-step explanation:

Given polynomial = √2x² - 3/√2x + 1/√2 = 0

=> 2x²-3x+1 =0

√2

=>2x²-3x+1=0

Now,

D = b²-4ac

D= (-3)²-4×2×1

D= 9-8

D=0

Hence, D>0

Roots are real & distinct

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