Find the nature of roots of the quadratic equation 2xSquare - 6x+3=0
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Answered by
10
2x^2-6x+3=0
2x^2-(3+2)x+3=0
2x^2-3x-2x+3=0
2x(x-3)-2(x-3)=0
(x-3)(2x-2)=0
x=3, x=1
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Answered by
4
To find the nature of the roots we need to find the determinant, D
D=
p(x)= 2x² -6x+3
D= (-6)² - 4(2)(3)
= 36-24
=12
12 > 0 therefore the roots are real and distinct.
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