Question

Find the nature of roots of the quadratic equation 2xSquare - 6x+3=0

Answer 1

2x^2-6x+3=0

2x^2-(3+2)x+3=0

2x^2-3x-2x+3=0

2x(x-3)-2(x-3)=0

(x-3)(2x-2)=0

x=3, x=1

I hope you like this answer make me brilliant

Answer 2

To find the nature of the roots we need to find the determinant, D

D=

${b {}^{2} - 4ac \ }$

p(x)= 2x² -6x+3

D= (-6)² - 4(2)(3)

= 36-24

=12

12 > 0 therefore the roots are real and distinct.