find the nature of roots of the quadratic equation 3x^-4√3x+4=0.if the real roots exist :find them
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Formalaue for finding nature of roots is
D=b^2-4a×c
b=4√3
a=3x^2
c=4
Solution:
(4√3)^2 -4(3)(4)=0
48-48=0
0=0
here D=0
since D=0,two real routes are equal
Therefore, this equation has real routes
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