Question

Find the nature of roots of the quadratic equation

4x2

-3x+2=0​

Answer 1

Explanation:

4x^2 -3x +2 =0

nature of root = d = b^2-4ac

if b^2 -4ac = 0 ( real and equal root)

if b^2 > 0 ( real and distinct root )

if b^2< 0 ( no real root )

here ; (-3)^2 -4×4×2 = 9 - 32

as, 9- 32 = -23

here b^2 -4ac < 0

there fore no real root exist