Question

find The nature of roots of The quadratic equation 9 X square + 3 X + 1 = 0 ​

Answer 1

Step-by-step explanation:

⇒ comparing with ax2 + bx + c = 0 ∆

= b2 – 4ac = (3)2 – 4(1)(-1)

= 9 + 4 = 13 > 0

⇒ The roots are real and distinct