Find the nature of roots of the quadratic equation X2=16x+64=0
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Answer:
Step-by-step explanation:
i suppose its
x^2+16x+64=0
so using (a+b)^2=a^2+b^2+2ab
we get that
x^2+16x+64
=(x+8)^2=0
hence
x=-8 (real and equal roots)
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