Question

find the nature of roots of the x^2+9 =0​

Answer 1

Answer:

Roots of a quadratic can be either imaginary/real, rational/irrational and equal/unequal.

To determine this we use the discriminant (Δ ). If Δ < 0 then imaginary. If Δ >= 0 then real. If Δ = 0 then equal roots. If Δ = perfect square then rational. If Δ /= perfect square then irrational

For a(x^2) + bx + c, Δ = b^2 − 4ac

x^2 = 9

x^2 + 0x - 9 = 0

therefore a = 1, b = 0, c = 9

Δ= (0)^2 - 4*1*-9

Δ= 36

Therefore the roots are real, rational and unequal.

To calculate the value of the roots, factorise the quadratic.

x^2 - 9 = 0

(x-3)(x+3) = 0

x = -3, 3

Answer 2

Answer:

THE ANSWER IS ROOT 9   AND    MINUS ROOT 9

Step-by-step explanation:

EXPAND THE SUM AND BRING IT TO THE FORM OF a^2+b^2. then you get the equation and then you will get  the two solutions