Question

find the nature of rooys of equation 9 square +12 + 4 = 0​

Answer 1

Answer:

Roots are imaginary from discriminant.

Answer 2

Answer:

$\huge{\boxed{\sf{ROOTS\:ARE\:EQUAL\:AND\:RATIONAL}}}$

Step-by-step explanation:

$\huge{\boxed{\sf{SOLUTION-}}}$

$\huge{\boxed{\sf{METHOD-}}}$

$\huge{\boxed{\sf{MIDDLE\:TERM\:SPLITING}}}$

${9x}^{2} + 12x + 4 = 0 \\ 9 {x}^{2} + 6x + 6x + 4 = 0 \\ 3x(3x + 2) + 2(3x + 2) = 0 \\( 3x + 2)(3x + 2) = 0\\ 3x + 2 = 0 \\ 3x = - 2 \\ x = \frac{ - 2}{3} - - - - - 1st \: root \\ x = \frac{ - 2}{3} - - - - - 2nd \: root$

=)BOTH THE ROOTS ARE SAME AND IN RATIONAL .

SO, ROOTS ARE IN EQUAL AND RATIONAL