Question

Find the nature of the following quadratie equation :- 10x²–20x + 1 = 0​

Answer 1

Answer:

Real and distinct.

Step-by-step explanation:

D= b^2-4ac
substituting the values,
a= 10, b = -20, c= +1
D= (-20)^2 - 4(10)(1) = 400-40= 360>0

since D>0, the roots are real and distinct.



Please consider marking my answer as the brainliest.