Question

find the nature of the quadratic equation X square - 6 X + 9 equals to zero by using quadratic equation​

Answer 1

${x}^{2} - 6x + 9 = 0 \\ {x}^{2} - 3x - 3x + 9 = 0 \\ x(x - 3) - 3(x - 3) = 0 \\ (x - 3)(x - 3) = 0 \\ x = 3 \: and \: 3 \: \: ( + ve)$

Hence, the roots are positive so the nature of roots is Distinct and Real.

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