find the nature of the root of log2^(3–x)+log2^(1–x)=3
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Answer:
x = 5, - 1
Step-by-step explanation:
Given to find the nature of the root of log2^(3–x)+log2^(1–x)=3
log 2^(3 - x) + log 2^(1 - x) = 3
log₂(3 - x) (1 - x) = 3
log₂( 3 - x - 3x + x^2) = 3
2^3 = x^2 - 4x + 3
8 = x^2 - 4x + 3
x^2 - 4x -5 = 0
x^2 - 5x + x - 5 = 0
x(x - 5) + 1(x - 5) = 0
(x - 5)(x + 1) = 0
x = 5, -1
Nature of roots are one is positive and another is negative.
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