Find the nature of the root of the equation 2x2-3x+5=0
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Answer:
imaginary and unequal
Step-by-step explanation:
Given, 2x^2 - 3x + 5 =0
comparing the above equation with
ax^2 + bx+c=0, we get
a=2, b=-3, c=5
Now, b^2-4ac = (-3) ^2 -4(2) (5)
= 9-40
= - 31<0(i.e.,negative)
Therefore, the roots of the equation are imaginary and unequal.
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