Question

Find the nature of the root of the following quadratic equation if the real root exist find them. 2xsquare-6+3=0

Answer 1

Step-by-step explanation:

to find nature of roots

∆ = b²-4ac

2x² -6x +3 =0

∆ = 36 -4(2)(3)

= 36 - 24

∆ = 12

∆ > 0

therefore the roots are real and distinct