Question

find the nature of the root of the quadratic equation 4√3x²+5x-2√3=0​

Answer 1

Answer:

As you can see it is quadratic equation....

where, A=4$\sqrt{3\\}$   B=5    C=-2$\sqrt{3}$

Firstly find the value of $\sqrt{b^2-4ac}$

substitute the terms in equation and obtain a value

1) If value is greater than 0 then roots is real and distinct

2) If value is 0 then roots is real and equal

3) If value is lesser than 0 then there are no real root

Hope you will be able to obtain a right value.

Answer 2

answer real root

Step-by-step explanation:

4√3x²+5x-2√3=0 .........1 eq.

comparing 1 eq. with ax²+bx+c

we get :-

a= 4√3

b=5

and c=-2√3

discrimination D = b²-4ac

= 5²-4×4√3×-2√3

= 25 +96

=121

121 is greater than 0

so it is real root

Hope this will help you a lot