Question

find the nature of the roots 2x²-42+3=0​

Answer 1

Answer:

Step-by-step explanation:

In 2x²-42x+3=0 ((a=2,b=-42,c=3))

So, D=b²-4ac

=(-42)²-4×2×3=1764-24=1740

as D>0 then, the roots are un-equal and real roots.