Math, asked by nirmalih34gmailcom13, 8 months ago

find the nature of the roots 2x2 - √5x + 1 = 0​

Answers

Answered by Anonymous
3

2 {x}^{2}  -  \sqrt{5} x + 1 \\  \\ d =  {b}^{2}  - 4ac \\  \\  =  {( -  \sqrt{5}) }^{2}  - 4 \times 2 \times 1 \\  \\  = 5 - 8 \\  \\  =  - 3 \\  \\ since \: d < 0 \\ the \: roots \: are \: not \: real

Answered by jahnavi61
0

Answer:

roots are complex and conjugate to each other

Step-by-step explanation:

2x^2-√5x+1

a=2,b=-√5,c=1

D=b^2-4ac

=(-√5)^2-4(2)(1)

=5-8

=(-3)

D<0

therefore roots are complex and conjugate to each other

Mark as you wish

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