Question

find the nature of the roots √3x^2+10x-8√3=0​

Answer 1

Answer:

comapre the equation with

ax^2+bx+c

a=√3 , b=10 , c=8√3

b^2-4ac=(10)^2-4(√3)(8√3)

=100-72

=96

Roots are real and unequal