Question

find the nature of the roots 6 x square minus x minus 2 is equals to zero​

Answer 1

Step-by-step explanation:

to make nature of roots

we use formula

b²-4ac

so

here a=6 b= -1 c=-2

= (-1)² - 4(6)(-2)

= 1-24(-2)

= 1- (-48)

= 48

hence it is more than zero

so it have real and distinct roots

where ∆>0

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Answer 2

Answer:

The roots are real and distinct.

Step-by-step explanation:

Here, a= 6, b= -1, c= -2

as discriminant D = b^2 - 4ac, defines nature of roots. Therefore,

by putting values

D= (-1)^2 - 4 (6)(-2) = 1 - (-48) = 1 + 48 = 49 > 0

i.e. if D >0 , roots are real and distinct.

Note: if D=0 , roots are real and equal.

and if D < 0 , roots are (conjugate) complex numbers.